3(4a-4)^2-5(4a-4)-2)=0

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Solution for 3(4a-4)^2-5(4a-4)-2)=0 equation: 



3(4a-4)^2-5(4a-4)-2)=0

We add all the numbers together, and all the variables

3(4a-4)^2-5(4a-4)=0

We multiply parentheses

3(4a-4)^2-20a+20=0

We add all the numbers together, and all the variables

-20a+3(4a-4)^2+20=0

We move all terms containing a to the left, all other terms to the right

-20a+3(4a-4)^2=-20

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